(2n-8)(n-6)=0

Solution for (2n-8)(n-6)=0 equation:

(2n-8)(n-6)=0

We multiply parentheses ..

(+2n^2-12n-8n+48)=0

We get rid of parentheses

2n^2-12n-8n+48=0

We add all the numbers together, and all the variables

2n^2-20n+48=0

a = 2; b = -20; c = +48;
Δ = b2-4ac
Δ = -202-4·2·48
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4}{2*2}=\frac{16}{4}
=4
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4}{2*2}=\frac{24}{4}
=6
$