/8x+5-6x=25

Solution for /8x+5-6x=25 equation:

/8x+5-6x=25

We move all terms to the left:

/8x+5-6x-(25)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We add all the numbers together, and all the variables

-6x+/8x-20=0

We multiply all the terms by the denominator


-6x*8x-20*8x+=0

We add all the numbers together, and all the variables

-6x*8x-20*8x=0

Wy multiply elements

-48x^2-160x=0

a = -48; b = -160; c = 0;
Δ = b2-4ac
Δ = -1602-4·(-48)·0
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-160}{2*-48}=\frac{0}{-96}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+160}{2*-48}=\frac{320}{-96}
=-3+1/3
$