6(x+3)+3(x+2)=64

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Solution for 6(x+3)+3(x+2)=64 equation: 



6(x+3)+3(x+2)=64

We move all terms to the left:

6(x+3)+3(x+2)-(64)=0

We multiply parentheses

6x+3x+18+6-64=0

We add all the numbers together, and all the variables

9x-40=0

We move all terms containing x to the left, all other terms to the right

9x=40

x=40/9

x=4+4/9

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