/5x+4-(2x-63)=12x+44

Solution for /5x+4-(2x-63)=12x+44 equation:

/5x+4-(2x-63)=12x+44

We move all terms to the left:

/5x+4-(2x-63)-(12x+44)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We get rid of parentheses

/5x-2x-12x+63-44+4=0

We multiply all the terms by the denominator


-2x*5x-12x*5x+63*5x-44*5x+4*5x+=0

We add all the numbers together, and all the variables

-2x*5x-12x*5x+63*5x-44*5x+4*5x=0

Wy multiply elements

-10x^2-60x^2+315x-220x+20x=0

We add all the numbers together, and all the variables

-70x^2+115x=0

a = -70; b = 115; c = 0;
Δ = b2-4ac
Δ = 1152-4·(-70)·0
Δ = 13225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13225}=115$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(115)-115}{2*-70}=\frac{-230}{-140}
=1+9/14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(115)+115}{2*-70}=\frac{0}{-140}
=0
$