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3(x-4)-4(x-3)=-(x-2)
We move all terms to the left:
3(x-4)-4(x-3)-(-(x-2))=0
We multiply parentheses
3x-4x-(-(x-2))-12+12=0
We calculate terms in parentheses: -(-(x-2)), so:We add all the numbers together, and all the variables
-(x-2)
We get rid of parentheses
-x+2
We add all the numbers together, and all the variables
-1x+2
Back to the equation:
-(-1x+2)
-1x-(-1x+2)=0
We get rid of parentheses
-1x+1x-2=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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