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/3a+2a+7=12
We move all terms to the left:
/3a+2a+7-(12)=0
Domain of the equation: 3a!=0We add all the numbers together, and all the variables
a!=0/3
a!=0
a∈R
2a+/3a-5=0
We multiply all the terms by the denominator
2a*3a-5*3a+=0
We add all the numbers together, and all the variables
2a*3a-5*3a=0
Wy multiply elements
6a^2-15a=0
a = 6; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·6·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*6}=\frac{0}{12} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*6}=\frac{30}{12} =2+1/2 $
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