/2s+s+12=132.

Solution for /2s+s+12=132. equation:

/2s+s+12=132.

We move all terms to the left:

/2s+s+12-(132.)=0


Domain of the equation: 2s!=0

s!=0/2

s!=0

s∈R


We add all the numbers together, and all the variables

/2s+s+12-132=0

We add all the numbers together, and all the variables

s+/2s-120=0

We multiply all the terms by the denominator


s*2s-120*2s+=0

We add all the numbers together, and all the variables

s*2s-120*2s=0

Wy multiply elements

2s^2-240s=0

a = 2; b = -240; c = 0;
Δ = b2-4ac
Δ = -2402-4·2·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-240}{2*2}=\frac{0}{4}
=0
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+240}{2*2}=\frac{480}{4}
=120
$