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22x-7-13x=3x(3x-3)+2
We move all terms to the left:
22x-7-13x-(3x(3x-3)+2)=0
We add all the numbers together, and all the variables
9x-(3x(3x-3)+2)-7=0
We calculate terms in parentheses: -(3x(3x-3)+2), so:We get rid of parentheses
3x(3x-3)+2
We multiply parentheses
9x^2-9x+2
Back to the equation:
-(9x^2-9x+2)
-9x^2+9x+9x-2-7=0
We add all the numbers together, and all the variables
-9x^2+18x-9=0
a = -9; b = 18; c = -9;
Δ = b2-4ac
Δ = 182-4·(-9)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-18}{-18}=1$
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