/2r+2(3/4r-1)=1/4r+6

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Solution for /2r+2(3/4r-1)=1/4r+6 equation: 



/2r+2(3/4r-1)=1/4r+6

We move all terms to the left:

/2r+2(3/4r-1)-(1/4r+6)=0



Domain of the equation: 2r!=0

r!=0/2

r!=0

r∈R





Domain of the equation: 4r-1)!=0

r∈R





Domain of the equation: 4r+6)!=0

r∈R



We multiply parentheses

/2r+6r-(1/4r+6)-2=0

We get rid of parentheses

/2r+6r-1/4r-6-2=0

We calculate fractions


6r+(*4r)/8r^2+(-2r)/8r^2-6-2=0

We add all the numbers together, and all the variables

6r+(+*4r)/8r^2+(-2r)/8r^2-6-2=0

We add all the numbers together, and all the variables

6r+(+*4r)/8r^2+(-2r)/8r^2-8=0

We multiply all the terms by the denominator


6r*8r^2+(+*4r)+(-2r)-8*8r^2=0

Wy multiply elements

48r^3-64r^2+(+*4r)+(-2r)=0

We get rid of parentheses

48r^3-64r^2+*4r-2r=0

We do not support erpression: r^3

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