/2k-3(4-k)=3k+4

Solution for /2k-3(4-k)=3k+4 equation:

/2k-3(4-k)=3k+4

We move all terms to the left:

/2k-3(4-k)-(3k+4)=0


Domain of the equation: 2k!=0

k!=0/2

k!=0

k∈R


We add all the numbers together, and all the variables

/2k-3(-1k+4)-(3k+4)=0

We multiply parentheses

/2k+3k-(3k+4)-12=0

We get rid of parentheses

/2k+3k-3k-4-12=0

We multiply all the terms by the denominator


3k*2k-3k*2k-4*2k-12*2k+=0

We add all the numbers together, and all the variables

3k*2k-3k*2k-4*2k-12*2k=0

Wy multiply elements

6k^2-6k^2-8k-24k=0

We add all the numbers together, and all the variables

-32k=0

k=0/-32

k=0

Równanie nie ma rozwiązania