.6-2(r-3)=6r+2(3r+1)-r

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Solution for .6-2(r-3)=6r+2(3r+1)-r equation: 



.6-2(r-3)=6r+2(3r+1)-r

We move all terms to the left:

.6-2(r-3)-(6r+2(3r+1)-r)=0

We add all the numbers together, and all the variables

-2(r-3)-(6r+2(3r+1)-r)+0.6=0

We multiply parentheses

-2r-(6r+2(3r+1)-r)+6+0.6=0



We calculate terms in parentheses: -(6r+2(3r+1)-r), so:

6r+2(3r+1)-r

We add all the numbers together, and all the variables

5r+2(3r+1)

We multiply parentheses

5r+6r+2

We add all the numbers together, and all the variables

11r+2

Back to the equation:

-(11r+2)



We add all the numbers together, and all the variables

-2r-(11r+2)+6.6=0

We get rid of parentheses

-2r-11r-2+6.6=0

We add all the numbers together, and all the variables

-13r+4.6=0

We move all terms containing r to the left, all other terms to the right

-13r=-4.6

r=-4.6/-13

r=2.875/8.125

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