(x+8)+x+4x=128

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Solution for (x+8)+x+4x=128 equation: 



(x+8)+x+4x=128

We move all terms to the left:

(x+8)+x+4x-(128)=0

We add all the numbers together, and all the variables

5x+(x+8)-128=0

We get rid of parentheses

5x+x+8-128=0

We add all the numbers together, and all the variables

6x-120=0

We move all terms containing x to the left, all other terms to the right

6x=120

x=120/6

x=20

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