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.5x(10x-4)=2x+6
We move all terms to the left:
.5x(10x-4)-(2x+6)=0
We multiply parentheses
10x^2-4x-(2x+6)=0
We get rid of parentheses
10x^2-4x-2x-6=0
We add all the numbers together, and all the variables
10x^2-6x-6=0
a = 10; b = -6; c = -6;
Δ = b2-4ac
Δ = -62-4·10·(-6)
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{69}}{2*10}=\frac{6-2\sqrt{69}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{69}}{2*10}=\frac{6+2\sqrt{69}}{20} $
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