.5-(n-4)-3=3(2n+2)

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Solution for .5-(n-4)-3=3(2n+2) equation: 



.5-(n-4)-3=3(2n+2)

We move all terms to the left:

.5-(n-4)-3-(3(2n+2))=0

We add all the numbers together, and all the variables

-(n-4)-(3(2n+2))-2.5=0

We get rid of parentheses

-n-(3(2n+2))+4-2.5=0



We calculate terms in parentheses: -(3(2n+2)), so:

3(2n+2)

We multiply parentheses

6n+6

Back to the equation:

-(6n+6)



We add all the numbers together, and all the variables

-1n-(6n+6)+1.5=0

We get rid of parentheses

-1n-6n-6+1.5=0

We add all the numbers together, and all the variables

-7n-4.5=0

We move all terms containing n to the left, all other terms to the right

-7n=4.5

n=4.5/-7

n=-3/4.6666666666667

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