.5-(n-4)-3=3(n+2)

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Solution for .5-(n-4)-3=3(n+2) equation: 



.5-(n-4)-3=3(n+2)

We move all terms to the left:

.5-(n-4)-3-(3(n+2))=0

We add all the numbers together, and all the variables

-(n-4)-(3(n+2))-2.5=0

We get rid of parentheses

-n-(3(n+2))+4-2.5=0



We calculate terms in parentheses: -(3(n+2)), so:

3(n+2)

We multiply parentheses

3n+6

Back to the equation:

-(3n+6)



We add all the numbers together, and all the variables

-1n-(3n+6)+1.5=0

We get rid of parentheses

-1n-3n-6+1.5=0

We add all the numbers together, and all the variables

-4n-4.5=0

We move all terms containing n to the left, all other terms to the right

-4n=4.5

n=4.5/-4

n=-1+0.5/4

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