.4(n-12)=n+12

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Solution for .4(n-12)=n+12 equation: 



.4(n-12)=n+12

We move all terms to the left:

.4(n-12)-(n+12)=0

We multiply parentheses

0.4n-(n+12)-4.8=0

We get rid of parentheses

0.4n-n-12-4.8=0

We add all the numbers together, and all the variables

-0.6n-16.8=0

We move all terms containing n to the left, all other terms to the right

-0.6n=16.8

n=16.8/-0.6

n=-28

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