(3/2)x+-4=13

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Solution for (3/2)x+-4=13 equation: 



(3/2)x+-4=13

We move all terms to the left:

(3/2)x+-4-(13)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



determiningTheFunctionDomain
(3/2)x-4-13+=0

We add all the numbers together, and all the variables

(+3/2)x-4-13+=0

We add all the numbers together, and all the variables

(+3/2)x=0

We multiply parentheses

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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