.111=((2x)(2(1.1+x))/((1.8-2x)(.2-2x)

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Solution for .111=((2x)(2(1.1+x))/((1.8-2x)(.2-2x) equation:



.111=((2x)(2(1.1+x))/((1.8-2x)(.2-2x)
We move all terms to the left:
.111-(((2x)(2(1.1+x))/((1.8-2x)(.2-2x))=0
Domain of the equation: ((1.8-2x)(.2-2x))+.111!=0
We move all terms containing x to the left, all other terms to the right
((1.8-2x)(.2-2x))!=-.111
x∈R
We add all the numbers together, and all the variables
-((2x(2(x+1.1))/((-2x+1.8)(-2x+0.2))+.111=0
We multiply parentheses ..
-((2x(2(x+1.1))/((+4x^2-0.4x-3.6x+0.36))+.111=0
We multiply all the terms by the denominator
-((2x(2(x+1.1))=0
We calculate terms in parentheses: -((2x(2(x+1.1)), so:
(2x(2(x+1.1)
We calculate terms in parentheses: +(2x(2(x+1.1), so:
2x(2(x+1.1
We calculate terms in parentheses: +(2x(2(x+1.1), so:
2x(2(x+1.1
We calculate terms in parentheses: +(2x(2(x+1.1), so:
2x(2(x+1.1
We calculate terms in parentheses: +(2x(2(x+1.1), so:
2x(2(x+1.1
We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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We calculate terms in parentheses: +(2x(2(x+1.1), so:
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