4(2x+3)=6x+28

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Solution for 4(2x+3)=6x+28 equation: 



4(2x+3)=6x+28

We move all terms to the left:

4(2x+3)-(6x+28)=0

We multiply parentheses

8x-(6x+28)+12=0

We get rid of parentheses

8x-6x-28+12=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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