.04(x)+.06(2x)=800

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Solution for .04(x)+.06(2x)=800 equation: 



.04(x)+.06(2x)=800

We move all terms to the left:

.04(x)+.06(2x)-(800)=0

We add all the numbers together, and all the variables

0.102x-800=0

We move all terms containing x to the left, all other terms to the right

0.102x=800

x=800/0.102

x=7843+0.01400000000001/0.102

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