3(u+3)=9u+21

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Solution for 3(u+3)=9u+21 equation: 



3(u+3)=9u+21

We move all terms to the left:

3(u+3)-(9u+21)=0

We multiply parentheses

3u-(9u+21)+9=0

We get rid of parentheses

3u-9u-21+9=0

We add all the numbers together, and all the variables

-6u-12=0

We move all terms containing u to the left, all other terms to the right

-6u=12

u=12/-6

u=-2

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