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-x=-36-7/10x
We move all terms to the left:
-x-(-36-7/10x)=0
Domain of the equation: 10x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-x-(-7/10x-36)=0
We add all the numbers together, and all the variables
-1x-(-7/10x-36)=0
We get rid of parentheses
-1x+7/10x+36=0
We multiply all the terms by the denominator
-1x*10x+36*10x+7=0
Wy multiply elements
-10x^2+360x+7=0
a = -10; b = 360; c = +7;
Δ = b2-4ac
Δ = 3602-4·(-10)·7
Δ = 129880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{129880}=\sqrt{4*32470}=\sqrt{4}*\sqrt{32470}=2\sqrt{32470}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-2\sqrt{32470}}{2*-10}=\frac{-360-2\sqrt{32470}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+2\sqrt{32470}}{2*-10}=\frac{-360+2\sqrt{32470}}{-20} $
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