-5(x+3)+3(4x-5)=6(x-4)+14

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Solution for -5(x+3)+3(4x-5)=6(x-4)+14 equation: 



-5(x+3)+3(4x-5)=6(x-4)+14

We move all terms to the left:

-5(x+3)+3(4x-5)-(6(x-4)+14)=0

We multiply parentheses

-5x+12x-(6(x-4)+14)-15-15=0



We calculate terms in parentheses: -(6(x-4)+14), so:

6(x-4)+14

We multiply parentheses

6x-24+14

We add all the numbers together, and all the variables

6x-10

Back to the equation:

-(6x-10)



We add all the numbers together, and all the variables

7x-(6x-10)-30=0

We get rid of parentheses

7x-6x+10-30=0

We add all the numbers together, and all the variables

x-20=0

We move all terms containing x to the left, all other terms to the right

x=20

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