(-3-8x)(1-2x)=0

Solution for (-3-8x)(1-2x)=0 equation:

(-3-8x)(1-2x)=0

We add all the numbers together, and all the variables

(-8x-3)(-2x+1)=0

We multiply parentheses ..

(+16x^2-8x+6x-3)=0

We get rid of parentheses

16x^2-8x+6x-3=0

We add all the numbers together, and all the variables

16x^2-2x-3=0

a = 16; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·16·(-3)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-14}{2*16}=\frac{-12}{32}
=-3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+14}{2*16}=\frac{16}{32}
=1/2
$