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-x=-2-4x-6-5/2x
We move all terms to the left:
-x-(-2-4x-6-5/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-x-(-4x-5/2x-8)=0
We add all the numbers together, and all the variables
-1x-(-4x-5/2x-8)=0
We get rid of parentheses
-1x+4x+5/2x+8=0
We multiply all the terms by the denominator
-1x*2x+4x*2x+8*2x+5=0
Wy multiply elements
-2x^2+8x^2+16x+5=0
We add all the numbers together, and all the variables
6x^2+16x+5=0
a = 6; b = 16; c = +5;
Δ = b2-4ac
Δ = 162-4·6·5
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{34}}{2*6}=\frac{-16-2\sqrt{34}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{34}}{2*6}=\frac{-16+2\sqrt{34}}{12} $
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