-3(v+3)=2v-9+3(3v+2)

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Solution for -3(v+3)=2v-9+3(3v+2) equation: 



-3(v+3)=2v-9+3(3v+2)

We move all terms to the left:

-3(v+3)-(2v-9+3(3v+2))=0

We multiply parentheses

-3v-(2v-9+3(3v+2))-9=0



We calculate terms in parentheses: -(2v-9+3(3v+2)), so:

2v-9+3(3v+2)

determiningTheFunctionDomain
2v+3(3v+2)-9

We multiply parentheses

2v+9v+6-9

We add all the numbers together, and all the variables

11v-3

Back to the equation:

-(11v-3)



We get rid of parentheses

-3v-11v+3-9=0

We add all the numbers together, and all the variables

-14v-6=0

We move all terms containing v to the left, all other terms to the right

-14v=6

v=6/-14

v=-3/7

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