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-x2-14x+48=0
We add all the numbers together, and all the variables
-1x^2-14x+48=0
a = -1; b = -14; c = +48;
Δ = b2-4ac
Δ = -142-4·(-1)·48
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{97}}{2*-1}=\frac{14-2\sqrt{97}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{97}}{2*-1}=\frac{14+2\sqrt{97}}{-2} $
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