(3x)+(2x+3)=7x-8

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Solution for (3x)+(2x+3)=7x-8 equation: 



(3x)+(2x+3)=7x-8

We move all terms to the left:

(3x)+(2x+3)-(7x-8)=0

We get rid of parentheses

3x+2x-7x+3+8=0

We add all the numbers together, and all the variables

-2x+11=0

We move all terms containing x to the left, all other terms to the right

-2x=-11

x=-11/-2

x=5+1/2

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