-n-4=5(n-2)

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Solution for -n-4=5(n-2) equation: 



-n-4=5(n-2)

We move all terms to the left:

-n-4-(5(n-2))=0

We add all the numbers together, and all the variables

-1n-(5(n-2))-4=0



We calculate terms in parentheses: -(5(n-2)), so:

5(n-2)

We multiply parentheses

5n-10

Back to the equation:

-(5n-10)



We get rid of parentheses

-1n-5n+10-4=0

We add all the numbers together, and all the variables

-6n+6=0

We move all terms containing n to the left, all other terms to the right

-6n=-6

n=-6/-6

n=1

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