8(2x-8)-2=8(x-3)+(6)

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Solution for 8(2x-8)-2=8(x-3)+(6) equation: 



8(2x-8)-2=8(x-3)+(6)

We move all terms to the left:

8(2x-8)-2-(8(x-3)+(6))=0

We multiply parentheses

16x-(8(x-3)+6)-64-2=0



We calculate terms in parentheses: -(8(x-3)+6), so:

8(x-3)+6

We multiply parentheses

8x-24+6

We add all the numbers together, and all the variables

8x-18

Back to the equation:

-(8x-18)



We add all the numbers together, and all the variables

16x-(8x-18)-66=0

We get rid of parentheses

16x-8x+18-66=0

We add all the numbers together, and all the variables

8x-48=0

We move all terms containing x to the left, all other terms to the right

8x=48

x=48/8

x=6

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