-n+3(1+3n)=4n+19

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Solution for -n+3(1+3n)=4n+19 equation: 



-n+3(1+3n)=4n+19

We move all terms to the left:

-n+3(1+3n)-(4n+19)=0

We add all the numbers together, and all the variables

-n+3(3n+1)-(4n+19)=0

We add all the numbers together, and all the variables

-1n+3(3n+1)-(4n+19)=0

We multiply parentheses

-1n+9n-(4n+19)+3=0

We get rid of parentheses

-1n+9n-4n-19+3=0

We add all the numbers together, and all the variables

4n-16=0

We move all terms containing n to the left, all other terms to the right

4n=16

n=16/4

n=4

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