-g+2(3+g)=+4(g+1)

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Solution for -g+2(3+g)=+4(g+1) equation: 



-g+2(3+g)=+4(g+1)

We move all terms to the left:

-g+2(3+g)-(+4(g+1))=0

We add all the numbers together, and all the variables

-g+2(g+3)-(+4(g+1))=0

We add all the numbers together, and all the variables

-1g+2(g+3)-(+4(g+1))=0

We multiply parentheses

-1g+2g-(+4(g+1))+6=0



We calculate terms in parentheses: -(+4(g+1)), so:

+4(g+1)

determiningTheFunctionDomain
4(g+1)

We multiply parentheses

4g+4

Back to the equation:

-(4g+4)



We add all the numbers together, and all the variables

g-(4g+4)+6=0

We get rid of parentheses

g-4g-4+6=0

We add all the numbers together, and all the variables

-3g+2=0

We move all terms containing g to the left, all other terms to the right

-3g=-2

g=-2/-3

g=2/3

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