-d-4(4d-8)=3(-8d-1)

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Solution for -d-4(4d-8)=3(-8d-1) equation: 



-d-4(4d-8)=3(-8d-1)

We move all terms to the left:

-d-4(4d-8)-(3(-8d-1))=0

We add all the numbers together, and all the variables

-1d-4(4d-8)-(3(-8d-1))=0

We multiply parentheses

-1d-16d-(3(-8d-1))+32=0



We calculate terms in parentheses: -(3(-8d-1)), so:

3(-8d-1)

We multiply parentheses

-24d-3

Back to the equation:

-(-24d-3)



We add all the numbers together, and all the variables

-17d-(-24d-3)+32=0

We get rid of parentheses

-17d+24d+3+32=0

We add all the numbers together, and all the variables

7d+35=0

We move all terms containing d to the left, all other terms to the right

7d=-35

d=-35/7

d=-5

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