(x)=-14(x+4)(x-8)

Solution for (x)=-14(x+4)(x-8) equation:

(x)=-14(x+4)(x-8)

We move all terms to the left:

(x)-(-14(x+4)(x-8))=0

We multiply parentheses ..

-(-14(+x^2-8x+4x-32))+x=0


We calculate terms in parentheses: -(-14(+x^2-8x+4x-32)), so:

-14(+x^2-8x+4x-32)

We multiply parentheses

-14x^2+112x-56x+448

We add all the numbers together, and all the variables

-14x^2+56x+448

Back to the equation:

-(-14x^2+56x+448)


We get rid of parentheses

14x^2-56x+x-448=0

We add all the numbers together, and all the variables

14x^2-55x-448=0

a = 14; b = -55; c = -448;
Δ = b2-4ac
Δ = -552-4·14·(-448)
Δ = 28113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{28113}}{2*14}=\frac{55-\sqrt{28113}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{28113}}{2*14}=\frac{55+\sqrt{28113}}{28}
$