-b-(13-4b)=-3(5-9b)+6

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Solution for -b-(13-4b)=-3(5-9b)+6 equation: 



-b-(13-4b)=-3(5-9b)+6

We move all terms to the left:

-b-(13-4b)-(-3(5-9b)+6)=0

We add all the numbers together, and all the variables

-b-(-4b+13)-(-3(-9b+5)+6)=0

We add all the numbers together, and all the variables

-1b-(-4b+13)-(-3(-9b+5)+6)=0

We get rid of parentheses

-1b+4b-(-3(-9b+5)+6)-13=0



We calculate terms in parentheses: -(-3(-9b+5)+6), so:

-3(-9b+5)+6

We multiply parentheses

27b-15+6

We add all the numbers together, and all the variables

27b-9

Back to the equation:

-(27b-9)



We add all the numbers together, and all the variables

3b-(27b-9)-13=0

We get rid of parentheses

3b-27b+9-13=0

We add all the numbers together, and all the variables

-24b-4=0

We move all terms containing b to the left, all other terms to the right

-24b=4

b=4/-24

b=-1/6

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