3/4c+1/2c=3/7

Solution for 3/4c+1/2c=3/7 equation:

3/4c+1/2c=3/7

We move all terms to the left:

3/4c+1/2c-(3/7)=0


Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R


We add all the numbers together, and all the variables

3/4c+1/2c-(+3/7)=0

We get rid of parentheses

3/4c+1/2c-3/7=0

We calculate fractions


(-48c^2)/392c^2+294c/392c^2+196c/392c^2=0

We multiply all the terms by the denominator


(-48c^2)+294c+196c=0

We add all the numbers together, and all the variables

(-48c^2)+490c=0

We get rid of parentheses

-48c^2+490c=0

a = -48; b = 490; c = 0;
Δ = b2-4ac
Δ = 4902-4·(-48)·0
Δ = 240100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{240100}=490$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(490)-490}{2*-48}=\frac{-980}{-96}
=10+5/24
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(490)+490}{2*-48}=\frac{0}{-96}
=0
$