-98x2=-18

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Solution for -98x2=-18 equation:



-98x^2=-18
We move all terms to the left:
-98x^2-(-18)=0
We add all the numbers together, and all the variables
-98x^2+18=0
a = -98; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·(-98)·18
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*-98}=\frac{-84}{-196} =3/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*-98}=\frac{84}{-196} =-3/7 $

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