-8y(2y+3)-12=14y-6y+4

Solution for -8y(2y+3)-12=14y-6y+4 equation:

-8y(2y+3)-12=14y-6y+4

We move all terms to the left:

-8y(2y+3)-12-(14y-6y+4)=0

We add all the numbers together, and all the variables

-8y(2y+3)-(8y+4)-12=0

We multiply parentheses

-16y^2-24y-(8y+4)-12=0

We get rid of parentheses

-16y^2-24y-8y-4-12=0

We add all the numbers together, and all the variables

-16y^2-32y-16=0

a = -16; b = -32; c = -16;
Δ = b2-4ac
Δ = -322-4·(-16)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{32}{-32}=-1$