(2/3)x+(2/3)x=7/8

Solution for (2/3)x+(2/3)x=7/8 equation:

(2/3)x+(2/3)x=7/8

We move all terms to the left:

(2/3)x+(2/3)x-(7/8)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x+(+2/3)x-(+7/8)=0

We multiply parentheses

2x^2+2x^2-(+7/8)=0

We get rid of parentheses

2x^2+2x^2-7/8=0

We multiply all the terms by the denominator


2x^2*8+2x^2*8-7=0

Wy multiply elements

16x^2+16x^2-7=0

We add all the numbers together, and all the variables

32x^2-7=0

a = 32; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·32·(-7)
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{14}}{2*32}=\frac{0-8\sqrt{14}}{64}
=-\frac{8\sqrt{14}}{64}
=-\frac{\sqrt{14}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{14}}{2*32}=\frac{0+8\sqrt{14}}{64}
=\frac{8\sqrt{14}}{64}
=\frac{\sqrt{14}}{8}
$