-8x(4x-5)=-10-7x

Solution for -8x(4x-5)=-10-7x equation:

-8x(4x-5)=-10-7x

We move all terms to the left:

-8x(4x-5)-(-10-7x)=0

We add all the numbers together, and all the variables

-8x(4x-5)-(-7x-10)=0

We multiply parentheses

-32x^2+40x-(-7x-10)=0

We get rid of parentheses

-32x^2+40x+7x+10=0

We add all the numbers together, and all the variables

-32x^2+47x+10=0

a = -32; b = 47; c = +10;
Δ = b2-4ac
Δ = 472-4·(-32)·10
Δ = 3489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{3489}}{2*-32}=\frac{-47-\sqrt{3489}}{-64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{3489}}{2*-32}=\frac{-47+\sqrt{3489}}{-64}
$