-8b+2+10b=2(b+3)-4

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Solution for -8b+2+10b=2(b+3)-4 equation: 



-8b+2+10b=2(b+3)-4

We move all terms to the left:

-8b+2+10b-(2(b+3)-4)=0

We add all the numbers together, and all the variables

2b-(2(b+3)-4)+2=0



We calculate terms in parentheses: -(2(b+3)-4), so:

2(b+3)-4

We multiply parentheses

2b+6-4

We add all the numbers together, and all the variables

2b+2

Back to the equation:

-(2b+2)



We get rid of parentheses

2b-2b-2+2=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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