7(r+4)-5r=-4(1+2r)

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Solution for 7(r+4)-5r=-4(1+2r) equation: 



7(r+4)-5r=-4(1+2r)

We move all terms to the left:

7(r+4)-5r-(-4(1+2r))=0

We add all the numbers together, and all the variables

7(r+4)-5r-(-4(2r+1))=0

We add all the numbers together, and all the variables

-5r+7(r+4)-(-4(2r+1))=0

We multiply parentheses

-5r+7r-(-4(2r+1))+28=0



We calculate terms in parentheses: -(-4(2r+1)), so:

-4(2r+1)

We multiply parentheses

-8r-4

Back to the equation:

-(-8r-4)



We add all the numbers together, and all the variables

2r-(-8r-4)+28=0

We get rid of parentheses

2r+8r+4+28=0

We add all the numbers together, and all the variables

10r+32=0

We move all terms containing r to the left, all other terms to the right

10r=-32

r=-32/10

r=-3+1/5

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