-8=1/3(3q+12)

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Solution for -8=1/3(3q+12) equation: 



-8=1/3(3q+12)

We move all terms to the left:

-8-(1/3(3q+12))=0



Domain of the equation: 3(3q+12))!=0

q∈R



We multiply all the terms by the denominator


-(1-8*3(3q+12))=0



We calculate terms in parentheses: -(1-8*3(3q+12)), so:

1-8*3(3q+12)

determiningTheFunctionDomain
-8*3(3q+12)+1

Wy multiply elements

-24q(3+1

Back to the equation:

-(-24q(3+1)



We add all the numbers together, and all the variables

-(-24q4=0

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