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-8/3x+3/2x=-7/6
We move all terms to the left:
-8/3x+3/2x-(-7/6)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-8/3x+3/2x+7/6=0
We calculate fractions
84x^2/216x^2+(-576x)/216x^2+324x/216x^2=0
We multiply all the terms by the denominator
84x^2+(-576x)+324x=0
We add all the numbers together, and all the variables
84x^2+324x+(-576x)=0
We get rid of parentheses
84x^2+324x-576x=0
We add all the numbers together, and all the variables
84x^2-252x=0
a = 84; b = -252; c = 0;
Δ = b2-4ac
Δ = -2522-4·84·0
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{63504}=252$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-252)-252}{2*84}=\frac{0}{168} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-252)+252}{2*84}=\frac{504}{168} =3 $
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