-8(4z-2)=34-7z

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Solution for -8(4z-2)=34-7z equation: 



-8(4z-2)=34-7z

We move all terms to the left:

-8(4z-2)-(34-7z)=0

We add all the numbers together, and all the variables

-8(4z-2)-(-7z+34)=0

We multiply parentheses

-32z-(-7z+34)+16=0

We get rid of parentheses

-32z+7z-34+16=0

We add all the numbers together, and all the variables

-25z-18=0

We move all terms containing z to the left, all other terms to the right

-25z=18

z=18/-25

z=-18/25

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