If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+50x=0
a = 5; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·5·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*5}=\frac{-100}{10} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*5}=\frac{0}{10} =0 $
| 7x-5-3x=15 | | 2w+1/1w+2=1/2 | | -4+5(8b-1)=39-8b | | 4(2x+9)=-13+1 | | 10w+3/5w+6=1/2 | | 7x/5=5x/3 | | $85+20w=$390 | | -4k-k=15 | | -4(3v-1)=4-8v | | 8-2b=-2(b=-3b=0b=5) | | 3(3n+3)=9(9n+6)+4 | | 6(x-5)-5=-35 | | 2w/1w+1/2=1/2 | | b+6=3(b-4) | | 1y-7=27 | | 19x-9=13x-27 | | 8(v-2=5(v+3)+8 | | 7(5x-4)-2=50-5x | | 7=-4k-4+3 | | 6x-10-8=9+4x-4x | | 3/4(4+2x)=1/2x | | 1.25x-6.50=20 | | 2/3x4=5 | | 2=p+5+1 | | X+2=-12-x | | 23+2x=49 | | 8x+11+12x-1=x | | -8-5n=63+3n | | −3−6x−4+5x=−x−8+x | | 3x-5=2(-6+5x) | | 17-7b=-6(5b+8) | | 7x-10+18=9x-11 |