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-7x^2=-488
We move all terms to the left:
-7x^2-(-488)=0
We add all the numbers together, and all the variables
-7x^2+488=0
a = -7; b = 0; c = +488;
Δ = b2-4ac
Δ = 02-4·(-7)·488
Δ = 13664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13664}=\sqrt{16*854}=\sqrt{16}*\sqrt{854}=4\sqrt{854}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{854}}{2*-7}=\frac{0-4\sqrt{854}}{-14} =-\frac{4\sqrt{854}}{-14} =-\frac{2\sqrt{854}}{-7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{854}}{2*-7}=\frac{0+4\sqrt{854}}{-14} =\frac{4\sqrt{854}}{-14} =\frac{2\sqrt{854}}{-7} $
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