-75+12Y+2=5(4y-4)-5

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Solution for -75+12Y+2=5(4y-4)-5 equation: 



-75+12+2=5(4Y-4)-5

We move all terms to the left:

-75+12+2-(5(4Y-4)-5)=0

We add all the numbers together, and all the variables

-(5(4Y-4)-5)-61=0



We calculate terms in parentheses: -(5(4Y-4)-5), so:

5(4Y-4)-5

We multiply parentheses

20Y-20-5

We add all the numbers together, and all the variables

20Y-25

Back to the equation:

-(20Y-25)



We get rid of parentheses

-20Y+25-61=0

We add all the numbers together, and all the variables

-20Y-36=0

We move all terms containing Y to the left, all other terms to the right

-20Y=36

Y=36/-20

Y=-1+4/5

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