X+1+3+x+1=4(x+1)

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Solution for X+1+3+x+1=4(x+1) equation: 



X+1+3+X+1=4(X+1)

We move all terms to the left:

X+1+3+X+1-(4(X+1))=0

We add all the numbers together, and all the variables

2X-(4(X+1))+5=0



We calculate terms in parentheses: -(4(X+1)), so:

4(X+1)

We multiply parentheses

4X+4

Back to the equation:

-(4X+4)



We get rid of parentheses

2X-4X-4+5=0

We add all the numbers together, and all the variables

-2X+1=0

We move all terms containing X to the left, all other terms to the right

-2X=-1

X=-1/-2

X=1/2

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