-7(-8-2b)=28+10b

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Solution for -7(-8-2b)=28+10b equation: 



-7(-8-2b)=28+10b

We move all terms to the left:

-7(-8-2b)-(28+10b)=0

We add all the numbers together, and all the variables

-7(-2b-8)-(10b+28)=0

We multiply parentheses

14b-(10b+28)+56=0

We get rid of parentheses

14b-10b-28+56=0

We add all the numbers together, and all the variables

4b+28=0

We move all terms containing b to the left, all other terms to the right

4b=-28

b=-28/4

b=-7

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